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x^2+5x-18=482
We move all terms to the left:
x^2+5x-18-(482)=0
We add all the numbers together, and all the variables
x^2+5x-500=0
a = 1; b = 5; c = -500;
Δ = b2-4ac
Δ = 52-4·1·(-500)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*1}=\frac{40}{2} =20 $
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